A ball is projected at 30 m s−1 at 30° above level ground. Taking g = 10 m s−2, find the time of flight, the greatest height and the range.
- Vertical component = 30 sin 30° = 15 m s−1; horizontal component = 30 cos 30° = 26.0 m s−1.
- Time of flight T = 2 × 15 ÷ 10 = 3.0 s.
- Greatest height H = 152 ÷ (2 × 10) = 225 ÷ 20 = 11.25 m.
- Range R = 26.0 × 3.0 = 78 m (check: 900 × sin 60° ÷ 10 = 77.9 m).
Answer: T = 3.0 s, H = 11.25 m, R ≈ 78 m.