A = 2i + j and B = i + 3j. Find the angle between them and the area of the parallelogram they form.
- A·B = (2)(1) + (1)(3) = 5.
- |A| = √(4 + 1) = √5 and |B| = √(1 + 9) = √10, so |A||B| = √50 = 7.07.
- cos θ = 5 ÷ 7.07 = 0.707, so θ = 45°.
- A × B = (2 × 3 − 1 × 1)k = 5k, so the area is 5 (check: 7.07 × sin 45° = 5).
Answer: θ = 45° and the area is 5 square units.