Chlorine has two isotopes: chlorine-35 (75% abundance) and chlorine-37 (25% abundance). What is the relative atomic mass of chlorine?
- Multiply each mass by its abundance: 35 × 75 = 2625 and 37 × 25 = 925.
- Add them: 2625 + 925 = 3550.
- Divide by 100: 3550 ÷ 100 = 35.5.
Answer: 35.5 amu. It is nearer to 35 because chlorine-35 is the more abundant isotope.