A vessel contains 16 g of methane, CH4, and 6 g of hydrogen, H2. The total pressure is 2 atm. What is the partial pressure of methane? (C = 12, H = 1)
- Moles: CH4 = 16 ÷ 16 = 1 mol; H2 = 6 ÷ 2 = 3 mol. Total = 4 mol.
- Mole fraction of CH4 = 1 ÷ 4 = 0.25.
- Partial pressure = 0.25 × 2 atm = 0.5 atm.
Answer: 0.5 atm. Hydrogen exerts the other 1.5 atm, although its mass is smaller.