2.4 g of magnesium is burned in 3.2 g of oxygen. 2Mg + O2 → 2MgO. The actual mass of MgO obtained is 3.0 g. What is the percentage yield? (Mg = 24, O = 16)
- Moles: Mg = 2.4 ÷ 24 = 0.1 mol; O2 = 3.2 ÷ 32 = 0.1 mol.
- MgO possible: from Mg, 0.1 mol; from O2, 0.1 × 2 = 0.2 mol. Magnesium gives less, so it is the limiting reactant.
- Theoretical yield = 0.1 × 40 = 4.0 g of MgO.
- Percentage yield = (3.0 ÷ 4.0) × 100 = 75%.
Answer: 75%. Magnesium is the limiting reactant and oxygen is in excess.