25.0 cm3 of potassium hydroxide solution is neutralised by 15.0 cm3 of 0.20 mol/dm3 nitric acid. KOH + HNO3 → KNO3 + H2O. What is the concentration of the potassium hydroxide?
- Moles of HNO3 = 0.20 × (15.0 ÷ 1000) = 0.0030 mol.
- The equation shows 1 mol of KOH reacts with 1 mol of HNO3, so moles of KOH = 0.0030 mol.
- Volume of KOH = 25.0 ÷ 1000 = 0.0250 dm3.
- Concentration = 0.0030 ÷ 0.0250 = 0.12 mol/dm3.
Answer: 0.12 mol/dm3