A passenger of mass 70 kg is travelling at 15 m/s when the car crashes. An air bag brings the passenger to rest in 0.25 s. What is the average force on the passenger? Compare it with stopping in 0.050 s without the air bag.
- Change in momentum = m × Δv = 70 × 15 = 1050 kg m/s.
- With the air bag: F = 1050 ÷ 0.25 = 4200 N.
- Without it: F = 1050 ÷ 0.050 = 21 000 N, which is five times larger.
Answer: 4200 N with the air bag, compared with 21 000 N without it.