A car of mass 1500 kg travels at 30 m/s. The driver's reaction time is 0.60 s and the braking force is 7500 N. What is the stopping distance?
- Thinking distance = speed × reaction time = 30 × 0.60 = 18 m.
- Deceleration = F ÷ m = 7500 ÷ 1500 = 5.0 m/s2.
- Braking distance from v2 − u2 = 2as: s = 302 ÷ (2 × 5.0) = 900 ÷ 10 = 90 m.
- Stopping distance = 18 + 90 = 108 m.
Answer: 108 m