Propene, CH3CH=CH2, is shaken with bromine. Name the type of reaction, the electrophile and the product.
- The C=C bond is electron-rich, so it attracts electrophiles.
- The double bond pushes the electrons in the nearby Br–Br bond away, so the nearer bromine atom becomes Brδ+ and acts as the electrophile.
- The Br–Br bond breaks heterolytically and one Br atom joins each carbon of the double bond.
- Product: CH3CHBrCH2Br, with no double bond left.
Answer: Electrophilic addition; the product is 1,2-dibromopropane.