Ethane reacts with bromine in ultraviolet light. Write the two propagation steps and explain why a little butane is found in the products.
- Initiation gives bromine radicals: Br2 → 2Br•.
- Propagation 1: C2H6 + Br• → C2H5• + HBr.
- Propagation 2: C2H5• + Br2 → C2H5Br + Br•.
- Two ethyl radicals can meet in a termination step: 2C2H5• → C4H10.
Answer: The main products are bromoethane and HBr; butane forms when two ethyl radicals combine in a termination step.