N2(g) + O2(g) → 2NO(g), ΔH = +180 kJ. N2(g) + 2O2(g) → 2NO2(g), ΔH = +66 kJ. What is ΔH for 2NO(g) + O2(g) → 2NO2(g)?
- NO must be a reactant, so reverse the first equation: 2NO → N2 + O2, ΔH = −180 kJ.
- Keep the second equation as it is: N2 + 2O2 → 2NO2, ΔH = +66 kJ.
- Add them. N2 cancels and one O2 cancels, leaving 2NO + O2 → 2NO2.
- ΔH = −180 + 66 = −114 kJ.
Answer: ΔH = −114 kJ