0.050 mol of a salt dissolves in 100 g of water and the temperature falls by 3.0 °C. What is the enthalpy change of solution? (c = 4.18 J g−1 K−1)
- Q = mcΔT = 100 × 4.18 × 3.0 = 1254 J = 1.254 kJ.
- Per mole: 1.254 ÷ 0.050 = 25.1 kJ mol−1.
- The temperature fell, so heat was taken in: the process is endothermic and ΔH is positive.
Answer: ΔH = +25 kJ mol−1