Three genes lie on different chromosomes. In the cross AaBbDd × AaBbDd, what fraction of the offspring show the dominant phenotype for all three characters?
- Take one gene at a time: Aa × Aa gives 3/4 with the dominant phenotype.
- The same is true for Bb × Bb and Dd × Dd: 3/4 each.
- Multiply: 3/4 × 3/4 × 3/4 = 27/64.
Answer: 27/64 of the offspring.