A relaxed sarcomere is 2.2 μm long. Its A band is 1.5 μm and its H zone is 0.5 μm. It contracts to 1.9 μm. Find the new lengths of the A band, I band (total) and H zone.
- A band is the myosin length, which does not change: 1.5 μm.
- I band (total) = sarcomere − A band = 1.9 − 1.5 = 0.4 μm (it was 2.2 − 1.5 = 0.7 μm).
- The sarcomere shortened by 2.2 − 1.9 = 0.3 μm, and the H zone shortens by the same amount: 0.5 − 0.3 = 0.2 μm.
Answer: A band 1.5 μm, I band 0.4 μm, H zone 0.2 μm.