For the compound [Cr(H2O)4Cl2]Cl, find the oxidation number and coordination number of chromium, and name the compound.
- One Cl− lies outside the brackets, so the complex ion has a charge of +1.
- Oxidation number: x + 4(0) + 2(−1) = +1, so x = +3.
- Four H2O and two Cl− are six monodentate ligands: coordination number 6, octahedral.
- Name the ligands in alphabetical order (aqua, then chloro), then the metal, then the anion.
Answer: Chromium is +3 with coordination number 6; the name is tetraaquadichlorochromium(III) chloride.