Stoichiometry

MDCAT Chemistry · Chemistry · Fundamental concepts of chemistry. The idea in plain words, the rules to remember, the mistake to avoid and a worked example, written and checked by Mega Lecture.

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The idea

A balanced equation is a recipe written in moles. The numbers in front of the formulae give the mole ratio in which the substances react and form. Masses do not react in simple ratios, so every calculation goes through moles.

When the reactants are not mixed in the exact ratio, one of them runs out first. This is the limiting reagent. It decides how much product can form, and some of the other reactant is left over.

The amount of product worked out from the equation is the theoretical yield. The amount really collected, the actual yield, is usually smaller because of side reactions, reversible reactions and losses in handling.

Rules to remember

Common mistake

Students pick the limiting reagent by comparing masses. Change both masses into moles first, then compare them with the ratio in the equation.

Worked example

4.8 g of magnesium is heated with 1.6 g of oxygen: 2Mg + O2 → 2MgO. What is the maximum mass of magnesium oxide that can form? (O = 16, Mg = 24)

  1. Moles: Mg = 4.8 ÷ 24 = 0.20 mol; O2 = 1.6 ÷ 32 = 0.050 mol.
  2. 0.050 mol of O2 needs only 2 × 0.050 = 0.10 mol of Mg, so oxygen is the limiting reagent and magnesium is in excess.
  3. Moles of MgO = 2 × 0.050 = 0.10 mol.
  4. Mass of MgO = 0.10 × (24 + 16) = 0.10 × 40 = 4.0 g.

Answer: 4.0 g of MgO (2.4 g of magnesium is left over)

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