4.8 g of magnesium is heated with 1.6 g of oxygen: 2Mg + O2 → 2MgO. What is the maximum mass of magnesium oxide that can form? (O = 16, Mg = 24)
- Moles: Mg = 4.8 ÷ 24 = 0.20 mol; O2 = 1.6 ÷ 32 = 0.050 mol.
- 0.050 mol of O2 needs only 2 × 0.050 = 0.10 mol of Mg, so oxygen is the limiting reagent and magnesium is in excess.
- Moles of MgO = 2 × 0.050 = 0.10 mol.
- Mass of MgO = 0.10 × (24 + 16) = 0.10 × 40 = 4.0 g.
Answer: 4.0 g of MgO (2.4 g of magnesium is left over)