A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. Its molar mass is 180 g mol−1. What is its molecular formula? (H = 1, C = 12, O = 16)
- Moles in 100 g: C = 40.0 ÷ 12 = 3.33; H = 6.7 ÷ 1 = 6.7; O = 53.3 ÷ 16 = 3.33.
- Divide by the smallest (3.33): C : H : O = 1 : 2 : 1, so the empirical formula is CH2O.
- Empirical formula mass = 12 + 2 + 16 = 30, so n = 180 ÷ 30 = 6.
Answer: C6H12O6