A 50 Ω heater is connected to a supply V = 100√2 sin (120πt) volts, with t in seconds. Find the frequency and the average power.
- Compare with V = V0 sin ωt: ω = 120π rad s−1, so f = ω ÷ 2π = 120π ÷ 2π = 60 Hz.
- Peak voltage V0 = 100√2 V, so Vrms = 100√2 ÷ √2 = 100 V.
- P = Vrms2 ÷ R = 1002 ÷ 50 = 10 000 ÷ 50 = 200 W.
Answer: Frequency 60 Hz, average power 200 W.