An ideal transformer has 500 turns on its primary coil and 2000 turns on its secondary. The primary is connected to 110 V AC and the secondary supplies 0.50 A. Find the secondary voltage and the primary current.
- Vs = Vp × Ns/Np = 110 × 2000 ÷ 500 = 440 V.
- Power out = VsIs = 440 × 0.50 = 220 W = power in.
- Ip = 220 ÷ 110 = 2.0 A.
Answer: 440 V and 2.0 A