Water leaves a large open tank through a small hole of area 2.0 cm2 that is 1.8 m below the water surface. Taking g = 10 m s−2, find the speed of the water and the volume leaving each second.
- Speed of efflux v = √(2gh) = √(2 × 10 × 1.8) = √36 = 6.0 m s−1.
- Area = 2.0 cm2 = 2.0 × 10−4 m2.
- Volume per second = Av = 2.0 × 10−4 × 6.0 = 1.2 × 10−3 m3 s−1.
Answer: 6.0 m s−1; 1.2 × 10−3 m3 s−1, which is 1.2 litres per second.