A tiny water droplet of radius r falls through air with a terminal velocity of 1.2 cm s−1. Eight such droplets join to form one drop. Find the terminal velocity of the large drop.
- Volume ∝ r3. The volume is 8 times larger, so the radius is 2 times larger, because 23 = 8.
- From Stokes' law, vt ∝ r2, so the terminal velocity is 22 = 4 times larger.
- vt = 4 × 1.2 = 4.8 cm s−1.
Answer: 4.8 cm s−1.