A skater spins at 2.0 revolutions per second with a moment of inertia of 4.0 kg m2. She pulls her arms in and her moment of inertia becomes 1.6 kg m2. Find her new rate of spin.
- No external torque acts, so angular momentum is conserved: I1ω1 = I2ω2.
- The ratio works in any unit of spin rate: 4.0 × 2.0 = 1.6 × new rate.
- New rate = 8.0 ÷ 1.6 = 5.0 revolutions per second.
Answer: 5.0 revolutions per second (10π rad s−1).