An ambulance sounding a 660 Hz siren moves at 10 m s−1 towards a person standing still. The speed of sound is 340 m s−1. What frequency does the person hear?
- The source is approaching, so f′ = f × v/(v − vs).
- f′ = 660 × 340 ÷ (340 − 10) = 660 × 340 ÷ 330.
- 660 ÷ 330 = 2, so f′ = 2 × 340 = 680 Hz.
Answer: 680 Hz (higher than 660 Hz, as expected for an approaching source)