A speed–time graph is a straight line from 6 m/s at t = 0 to 14 m/s at t = 4 s. The speed then stays at 14 m/s for 5 s. Find the acceleration and the total distance travelled.
- Acceleration = gradient = (14 − 6) ÷ 4 = 8 ÷ 4 = 2 m/s2.
- First part is a trapezium: ½ × (6 + 14) × 4 = 40 m.
- Second part is a rectangle: 14 × 5 = 70 m.
- Total distance = 40 + 70 = 110 m.
Answer: Acceleration = 2 m/s², distance = 110 m