Line L passes through (1, 3) and (5, 11). Find the equation of the line through (4, 1) that is perpendicular to L.
- Gradient of L = (11 − 3) ÷ (5 − 1) = 8 ÷ 4 = 2.
- Perpendicular gradient = −1/2, because 2 × (−1/2) = −1.
- y − 1 = −(1/2)(x − 4), so y = −(1/2)x + 2 + 1.
Answer: y = −(1/2)x + 3